If some person can do a piece of work in 80 days, in how many days two times the number of such person will do half of that work ?
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let x be the number of people that can do 1 work in 80 days . and let required number of days be 'y' .
let original work = 1 units
new work = 1/ 2 units
let original number of persons = x
new number of persons
= 2 times of x = 2x
(x × 80)÷1 = [ (2x × y)÷(1 / 2) ]
80x = (2xy/ 1) × (1/ 2 )
80x = xy
y = 80x ÷ x
y = 80 days
Answer:
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required days = 80 days
let original work = 1 units
new work = 1/ 2 units
let original number of persons = x
new number of persons
= 2 times of x = 2x
(x × 80)÷1 = [ (2x × y)÷(1 / 2) ]
80x = (2xy/ 1) × (1/ 2 )
80x = xy
y = 80x ÷ x
y = 80 days
Answer:
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required days = 80 days
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