If son teta=3/5,then find the value of(tan teta+sec teta) 2
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Answer:
4
Step-by-step explanation:
As sinΘ = 3/5
cos²Θ+sin²Θ = 1 (Identity)
⇒cos²Θ = 1-sin²Θ
⇒cos²Θ = 1-(3/5)²
⇒cos²Θ = 1- 9/25 ( 3² = 9, 5²=25)
⇒cos²Θ = 16/25
⇒cosΘ = √16/25
⇒cosΘ=4/5 (√16/25 =4/5)
Now,
(tanΘ + secΘ)2
=(sinΘ/cosΘ + 1/cosΘ)2
={(3/5)/(4/5) + 1/(4/5)}2
=(3/4 + 5/4)2
=(8/4)2
=2*2
=4
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