Math, asked by advaith4585, 10 months ago

If squares of 2 consecutive positive integers differ by 1987. Then sum of these integers is​

Answers

Answered by Indian001
1

Answer:

Step-by-step explanation:

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Answered by Shravanp
0

Answer:

Step-by-step explanation:

Let the positive integer be x

A. T. Q.

X2-(x-1)2=1987

X2-(x2+1-2x)=1987

-1+2x=1987

2x=1988

X=994

X+1=995

X+(x+1)=994+995

=1989

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