If sum of 3 consecutive terms of an ap is 51 and product of 1st and 3rd term is 273
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let the numbers be x,x+1,x+2
sum=x+x+1+x+2=51
3x+3=51
3x=48
x=16
product of 1st &3rd term is 273
x(x+2)=273
x^2+2x=273
x^2+2x-273=0
x=16
numbers=16,17,18
sum=x+x+1+x+2=51
3x+3=51
3x=48
x=16
product of 1st &3rd term is 273
x(x+2)=273
x^2+2x=273
x^2+2x-273=0
x=16
numbers=16,17,18
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