In the given figure, ∆ABC congruent to ∆EDA. If X and Y are the points lying on AD and EG respectively such that AX/XC = EY/YG= 1. Then value of DX/FY is always ?
Options are
1) Greater than 1
2) Equal to 1
3) Less than 1
4) Equal to 3/2
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Answered by
10
2 hope it will help....
saurabhceiiest:
Please show me solution
Answered by
6
<EGF = <DGC = 90° - <C
<E = <A = 90° - <C
<E = <EGF = >EF = FG
FY is the median in the triangle FEG
FY is the perpendicular to ED
FE // AC (this is the equation 1)
Join BX
BX is the median of triangle ABC
BX = 1/2 AC = XC
<XBC = <C = DAE
ABFX is cyclic quadrilateral
<<AXF = 180° - <ABF = 90°
FX is perpendicular to AC (this equation will be 2)
so from equation 1 and 2
DXFY is a rectangle = DX = FY
DX/FY = 1
If there is any confusion please leave a comment below.
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