if sum of 3term 10th term is 9 and sum of 7th term and 15 term is 32 find a and d
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3rd term = a+2d.........(1)
10th term =a+9d........(2)
adding equation 1 and 2, we get:-
2a+11d
the sum of equation 1 and 2 is 9.
therefore
2a+11d=9................(3)
7th term = a+6d......(4)
15th term =a+14d....(5)
adding equation 4 and 5 we get:-
2a+20d
it is given that there sum is 32.
therefore
2a+20d=32..........(6)
subtracting equation 3 from equation 6,we get:-
9d=23
d=23/9
putting the value of d in equation 3 we get
2a + 11×23/9=9
2a+11×23=81
2a + 253 =81
2a=81-253
2a= 272
a=272/2
a=136
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