If sum of 5 consecutive even numbers is A then the sum of next set
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let the first even no. be X
X + (X+2) + (X+4) + (X+6) + (X+8) = A
5X + 20 = A
5X = A - 20. (1)
(X+10) + (X+12) + (X+14) + (X+16) + (X+18)
= 5X + 70
= A - 20 + 70. ( from eq.1)
= A + 50...
X + (X+2) + (X+4) + (X+6) + (X+8) = A
5X + 20 = A
5X = A - 20. (1)
(X+10) + (X+12) + (X+14) + (X+16) + (X+18)
= 5X + 70
= A - 20 + 70. ( from eq.1)
= A + 50...
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