if sum of first mth term of an ap is the same as the sum of its fierst nth term show that sum of it m+n =0
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Step-by-step explanation:
m/2{2a + (m-1)d} = n/2{2a + (n-1)d}
→2am + m^2d - md- 2an -n^2d + nd =0
→(m-n ){2a + (m+n-1)d}=0
→{2a+(m+n-1)d}=0
→(m+n)/2{2a + (m+n-1)d}=0
thus , S (m+n)=0
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Answer:
that is the right answer
Step-by-step explanation:
it
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