Question

If sum of first n terms of a series is S = 3n³ + 2n^2, then 6th term is​

Answer 1

Answer:

there are maths in to much classes but that was good

Answer 2

Answer:

295

Step-by-step explanation:

$\sf S_n = 3n^3 + 2n^2$

We can put n = 6 and n = 5 to find corresponding S values

When n = 6,

$\sf S_6 = 3(6)^3 + 2(6)^2$

[tex)\sf S_6 = 648 + 72[/tex]

$\sf S_6 = 720$

When n = 5,

$\sf S_7 = 3(5)^3 + 2(5)^2$

$\sf S_7 = 375 + 50$

$S_7 = 425$

As we know,

$\huge \boxed{a_n = S_n - S_{n-1}}$

Thus,

$\sf a_6 = S_6 - S_5$

Thus ,

$\sf a_6 = 720 - 425 = 295$

Thus the 6th term is 295

$\huge\color{#4FB3F6}\boxed{\colorbox{#4FB3F6}{\color{white}{Thanks}}}$