Question

if sum of roots of equation ax^2+bx+c=0 is equal to their product, then find the value of b+c.​

Answer 1

Answer:

zero

Step-by-step explanation:

hope it helps !

if any queries, can ask in comments !

Answer 2

Given :-

$\sf ax^2+bx+c=0\\ \\\dashrightarrow \sf \alpha+\beta= \alpha \beta$

To find :-

◆ b+c

A.T.Q :-

We know that ax^2+bx+c =0

$\dashrightarrow\tt a= Coefficient\ of \ x^2\\ \\ \dashrightarrow \tt b= coefficient\ of \ x \\ \\ \dashrightarrow \tt c= constant\ term$

$\longmapsto\sf \alpha+\beta= \dfrac{-b}{a}$

$\longmapsto\sf \alpha \beta= \dfrac{c}{a}$

So ,

$\longmapsto\sf \alpha+\beta= \alpha \beta\\ \\ \longmapsto\sf Put \:the\: values \\ \\ \longmapsto\sf \dfrac{-b}{\cancel{a}}=\dfrac{c}{\cancel{a}}\\ \\ \sf\:\dag a\:\: will \ be \ cancelled\\ \\ \longmapsto\sf -b=c$

$\boxed{\sf{-b=c}}$

• We have to find the value of b+c

$\dashrightarrow\tt b+ c \ \ [ put \ (-b ) \ \ in \ place \ of \ c ]\\ \\\dashrightarrow \tt b-b\\ \\ \dashrightarrow\tt 0$

$\bigstar{\boxed{\sf{b+c=0}}}$