If sum of squares of zeroes of polynomial 6x^2 +x+k is 25/36.Find the value of k and verify the value
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i think my solution is easy to understand
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kaushlendra2:
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let one zero be α
let other zero be β
b² - 4ac = 0
(1)² - 4(6)(k) = 0
1 - 24k = 0
1 = 24k
1/24 = k
k = 1/24
let other zero be β
b² - 4ac = 0
(1)² - 4(6)(k) = 0
1 - 24k = 0
1 = 24k
1/24 = k
k = 1/24
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