If Sum of term of an AP is 295 and first term 7 common diff = 5 Then find the value of no
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Answer:
a=7
d=5
n=?
sn=295
sn=n/2 [2a+(n-1)d]
295=n/2[2*7+(n-1)5]
295=n/2[14+5n-5]
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