Question

If Sum of term of an AP is 295 and first term 7 common diff = 5 Then find the value of no​

Answer 1

Answer:

a=7

d=5

n=?

sn=295

sn=n/2 [2a+(n-1)d]

295=n/2[2*7+(n-1)5]

295=n/2[14+5n-5]