If sum of the ages of 2 boys be 47 years ,as the product of their ages 550 .Find their present ages
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avneetkaur01:
Correct explanation with correct ans bro
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hi...
let age of one boy be x
age of second boy be y
x + y = 47
x = 47-y
xy = 550
(47 - y) y = 550
![- {y}^{2} - 47y - 550 = 0 - {y}^{2} - 47y - 550 = 0](https://tex.z-dn.net/?f=+-+%7By%7D%5E%7B2%7D+-+47y+-+550+%3D+0)
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![now \: factorise \: it now \: factorise \: it](https://tex.z-dn.net/?f=now+%5C%3A+factorise+%5C%3A+it)
REFER TO ATTACHMENT.......
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so y = 26
x = 47 - 26
x = 21
let age of one boy be x
age of second boy be y
x + y = 47
x = 47-y
xy = 550
(47 - y) y = 550
____________________________
REFER TO ATTACHMENT.......
______________________________
so y = 26
x = 47 - 26
x = 21
Attachments:
![](https://hi-static.z-dn.net/files/d88/f8e8d147763e7810452ba6a0d04b8957.jpg)
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