Question

If sum of the first n even natural numbers is S1 and sum of the first n odd
natural numbers is S2, then prove that n. S1 = (n+1)S2.​

Answer 1

Step-by-step explanation:

sum of n even numbers=s1

sum of n odd numbers=S2

sum=n(n+1)/2

if n=50

50×51/2

50 is even number and 51 is odd number

51=50+1

so,we can prove that n.s1=(n+1)S2

hope it helps you