Question

if sum of the number is 18 and the sum of their square is 290 find the number​

Answer 1

Step-by-step explanation:

$according \: to \: the \: question \\ x + y = 18 \\ {x}^{2} + {y}^{2} = 290$

$x + y = 18 \\ squaring \: both \: the \: numbers \\ = > {(x + y)}^{2} = {(18)}^{2} \\ = > {x}^{2} + 2xy + {y}^{2} = 324 \\ = > 2xy + 290 = 324 \\ = > 2xy = 324 - 290 \\ = > xy = \frac{34}{2} \\ = > xy = 17$

$factors \: of \: 17 \: whose \: sum \: is \: 18 \: is \\ 1 \: and17 \\ therefore \: x \: and \: y \: are \: 1 \: and \: 17 \: respectively$

Answer 2

Answer:

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