Question

If sum of the squares of zeroes of the
quadratic polynomial x^2 -8x +k is 40,find the
value of k.​

Answer 1

Answer:

$\alpha + \beta = 8 \\ \alpha \beta = k \\ ( \alpha + \beta ) ^{2} = 64 \\ { \alpha }^{2} + { \beta }^{2} + 2 \alpha \beta = 64 \\ { \alpha }^{2} + { \beta }^{2} = 64 - 2k \\ 40 = 64 - 2k \\ 2k = 24 \\ k = 12$

Step-by-step explanation:

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