If sum of the three numbers in A.P. is 78 and their product is 15470, then sum of squares of the three numbers is
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Answer:
Correct option is
D
2,−1,−4.
Let three no's in AP be a−d,a,a+d
Given, sum of three numbers =−3
Therefore, a−d+a+a+d=−3
⇒3a=−3
⇒a=−1
Also product of three numbers =8
Therefore, (a−d)a(a+d)=8
⇒a(a
2
−d
2
)=8
⇒(−1)(1−d
2
)=8
⇒1−d
2
=−8
⇒d
2
=9
⇒d=3 and d=−3
If a=−1 and d=3 numbers are −4,−1,2.
And if a=−1 and d=−3 numbers are 2,−1,−4.
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