Question

if sum of three consecutive terms of ap is 48 and the product of first and ladt term is 252 then d =

Answer 1

Hey !!





Let three consecutive terms of an AP be ( A - D ) , A and ( A + D ).




According to the question,




Sum of three consecutive terms = 48


A - D + A + A + D = 48



3A = 48



A = (48/3) = 16.





First term ( A ) = 16.








Again,




Product of first term and last term = 252




( A - D ) × ( A + D ) = 252




( A)² - ( D)² = 252



(16)² - ( D )² = 252




(D)² = 256 - 252




D² = 4




D = ✓4 = 2



Hence,



Common difference ( D ) = 2.

Answer 2

Hi dear

★ Here is your answer ★

suppose three consecutive terms of an AP be ( a - D ) , a and ( a + D )

a/q,

sum of three consecutive numbers = 48

A - D + A + A + D = 48

3a = 48

a= (48/3) = 16.

First term = 16.

Product of first and last number= 252

( a - d ) × ( a + d ) = 252

( A)² - ( d)² = 252

(16)² - ( d)² = 256

(d)² = 256 - 252

d = ✓4 = 2

Common difference = 2.

Hope it helps you ^_^