If sum of three prime no. is 100 and one of them exceeds other by 36 then find the largest no.
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let the prime no be x, x+36 ,y
A/Q
x +x+36 +y =100
2x +y =64
all three are prime so 2x should be a even number also to get sum as 100 y should be even number I. e 2
putting y =2
then 2x +x = 64
x=31
prime no are 31 ,67,2
largest is 67
hope this helps you
A/Q
x +x+36 +y =100
2x +y =64
all three are prime so 2x should be a even number also to get sum as 100 y should be even number I. e 2
putting y =2
then 2x +x = 64
x=31
prime no are 31 ,67,2
largest is 67
hope this helps you
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