Question

if sum of two digit number and the number formed interchanging its digits is 110 15 is subtracted from the first number in your number is 4 more than the five times the sum of the digits in the first number find the value of first number

Answer 1

here is your answer mate. But check in your attached pic it is given that 10 in subtracted while you have written 15 in subtracted. If there is any doubt pls leave a comment.

Answer 2

Here is your solution

mistake of typing instead of 15 it will be 10 we can see fig also.

Let the digit at ones place = y
Let the digit at tens place = x

original number = 10x + y 

Number formed by reversing the digits =10y + x

On adding original number and Reversed number.

10x+y+10y+x = 110
11x + 11y = 110
11 (x + y ) = 110
x + y = 10
x = 10 - y ................................................. (1)

on subtracting 10 from the original number , we get = 10x + y -10
and


4 more than 5 times the sum of digits = 5(x + y) + 4

A/q
 
10x + y -10 = 5(x + y) + 4
10x + y -10 = 5x +5y + 4
10x -5x + y -5y = 10 +4
5x - 4y = 14.................................................. (2)


putting the value of x in equation (2)

5x - 4y = 14
5×(10-y) - 4y = 14
50-5y-4y =14
-9y = 14 -50
-9y = -36
y = 4


Now

x = 10-y
x = 10 - 4
x = 6


original number = 10x + y  = 10×6+4 = 64

Hope it helps you