Math, asked by isaacshajan1234, 7 months ago

Solve this quadratic equation.....
The person who replies first I will mark as brainlist .......l​

Attachments:

Answers

Answered by nithya3322
0

Step-by-step explanation:

Given,

8y^2 - 9y + 1 = 0

8y^2 - 8y - y + 1 = 0

8y(y - 1) - 1(y - 1) = 0

(8y - 1)(y - 1) = 0

y = 1/8 , 1

Hope it helps...

Answered by Anonymous
4

8y²-9y+1=0

8y²-8y-1y+1

8y(y-1)-1(y-1)

(y-1)(8y-1)

y=1,1/8

Similar questions