Solve this quadratic equation.....
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0
Step-by-step explanation:
Given,
8y^2 - 9y + 1 = 0
8y^2 - 8y - y + 1 = 0
8y(y - 1) - 1(y - 1) = 0
(8y - 1)(y - 1) = 0
y = 1/8 , 1
Hope it helps...
Answered by
4
8y²-9y+1=0
8y²-8y-1y+1
8y(y-1)-1(y-1)
(y-1)(8y-1)
y=1,1/8
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