Question

if sum of two natural numbers is 20 and product is 96 . find the number

Answer 1

let two natural numbers be x and y .
ATP;
x+y=20___eqn(1)
xy=96
x=96/y____eqn(2)

putting eqn (2) in eqn (1)
y+96/y=20
y×y - 20y + 96 = 0
then by mid-term splitting

y×y -12y-8y+96=0

y(y-12)-8(y-12)=0
(y-8) (y-12) =0



there are two values of y=8,12
when y=8 , x=12
when y=12 , x=8

H.P.

Answer 2

Answer:

Step-by-step explanation:

Let the two natural no are X andY so

According to the question

X+Y=20_(i)

X.Y=96-(ii)

From equation i

So let X=20-Y

Putting the value in (ii)

(96-y).Y=96

Y²-20Y-96=0

(Y²-12Y)(8Y-96)

Y(Y-12)-8(Y-12)=0

Y=8and12

Putting the value of Y in equation (I)

X+8=20and X+12=20

So X= 12and 8