if sum of two natural numbers is 20 and product is 96 . find the number
ram1854:
let two no. first be x and second be y. x+y=20
Answers
Answered by
1
let two natural numbers be x and y .
ATP;
x+y=20___eqn(1)
xy=96
x=96/y____eqn(2)
putting eqn (2) in eqn (1)
y+96/y=20
y×y - 20y + 96 = 0
then by mid-term splitting
y×y -12y-8y+96=0
y(y-12)-8(y-12)=0
(y-8) (y-12) =0
there are two values of y=8,12
when y=8 , x=12
when y=12 , x=8
H.P.
ATP;
x+y=20___eqn(1)
xy=96
x=96/y____eqn(2)
putting eqn (2) in eqn (1)
y+96/y=20
y×y - 20y + 96 = 0
then by mid-term splitting
y×y -12y-8y+96=0
y(y-12)-8(y-12)=0
(y-8) (y-12) =0
there are two values of y=8,12
when y=8 , x=12
when y=12 , x=8
H.P.
y×y - 20y + 96 = 0
Answered by
1
Answer:
Step-by-step explanation:
Let the two natural no are X andY so
According to the question
X+Y=20_(i)
X.Y=96-(ii)
From equation i
So let X=20-Y
Putting the value in (ii)
(96-y).Y=96
Y²-20Y-96=0
(Y²-12Y)(8Y-96)
Y(Y-12)-8(Y-12)=0
Y=8and12
Putting the value of Y in equation (I)
X+8=20and X+12=20
So X= 12and 8
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