Question

If sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are

Answer 1

Answer:

4

Step-by-step explanation:

Take two numbers x and y

We know the HCF of both the numbers is 81

And the product of two numbers is 1215

So we can write

81x + 81y = 1215

dividing by 81 on both the sides we get

x+ y = 15

Now you need to find different values of x and y where the HCF of both the numbers is 1

(1,14) (2,13) (4,11) and (7,8).

This we get totally 4 pairs