Math, asked by tbhosale1234, 1 year ago

if sum of zeroes of kx^2+2x+3k is equal to their product find k

Answers

Answered by Fuschia
27
Given -> kx² + 2x + 3k = 0

Sum of zeroes = -2/k
Product of zeroes = 3k/k = 3

A/Q --.> -2/k = 3
k = -2/3

Hence required value of k = -2/3

Hope This Helps You

Answered by sandeepbiswas267
5

Answer:

Step-by-step explanation:

Given -> kx² + 2x + 3k = 0

Sum of zeroes = -2/k

Product of zeroes = 3k/k = 3

A/Q --.> -2/k = 3

k = -2/3

Similar questions