if sum of zeroes of the polynomial f(y) =y^2+2y+3k is equal to their products, find the value of k.
Answers
Answered by
1
Hey
Here is your answer,
y^2 + 2y + 3k =0
Sum of zeroes = -b/a
=-2/1
=-2
Product of zeroes = c/a
=3k/1
=3k
Given that,
Sum of zeroes = Product of zeroes
-2 = -3/k
k=-2/-3
k=2/3
Hope it helps you!
Here is your answer,
y^2 + 2y + 3k =0
Sum of zeroes = -b/a
=-2/1
=-2
Product of zeroes = c/a
=3k/1
=3k
Given that,
Sum of zeroes = Product of zeroes
-2 = -3/k
k=-2/-3
k=2/3
Hope it helps you!
ironman777:
thnx a lot
Similar questions
Math,
8 months ago
History,
8 months ago
Math,
8 months ago
Biology,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Biology,
1 year ago