Question

if sum of zeros and product of zeros of p (x) =x square +(k-g) x+(k-1) are equal then find value of k​

Answer 1

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Answer 2

$\huge\mathbb{ \underline{ \underline{Answer}}}$

$\sf{Sum\:of\:zeroes\:=\:\frac{-b}{a}}$

$\sf{Sum\:of\:zeroes\:=\:\frac{-(k-g)}{1}\:=\:g-k}$

_____________________

$\rm{Product\:of\:zeroes\:=\:\frac{c}{a}}$

$\rm{Product\:of\:zeroes\:=\:\frac{(k-1)}{1}\:=\:k-1}$

$\bf{According\:to\: Question }$

$\tt{k-1\:=\:g-k}$

$\tt{k+k\:=\:g+1}$

$\tt{2k\:=\:g+1 }$

$\tt{k\:=\:\frac{g+1}{2}}$