If t_(1/2) of first order reaction is 40 min then the time required for the completion of 75% of the reaction will be
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t1/2=In2/k=0.4min
for 99.9%, at=1000.1a0=1000a0
kt=Inata0=In1000
(0.4In2.t=3In10
t=1.2×in2In10=4 min
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