If t is the parameter for one end of a focal chord of the parabola y^2=4ax than its length is
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Following are the options for this question:
(a) a(t+1t)2
(b) a(t−1t)2
(c) a(t+1t)
(d) a(t−1t)
The correct answer for this question is:
option A : a(t+1t)2
If there is any confusion, please leave a comment below.
Answered by
5
solution:
Y∧2 = 4ax
t1t2 = 1
AB = AS + BS
= at12 +a + at22 + a
= a(t12 + t22 + 2)
= a( t12 + 1/t1 + 2)
= a( t1 +1/t1)2
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