Question

If t1 and t2 are the lengths of tangents drawn from two conjugate points A, B then

Answer 1

Answer:

see the images you can understant easily

Answer 2

Answer:

AB² = t1² + t2²

Step-by-step explanation:

Given t1 and t2 are the lengths of tangents drawn from two conjugate points A , B.

Let 'r' be the radius and 'c' be the centre of the circle.

Since A and B are conjugate points of the circle,

so we have:

AB² = CA² + CB² - 2r²    .....................(1)

Now, CA² = t1² + r²   ..................(2)

and CB² = t2² + r²   ................(3)

From (1), (2) and (3), we get:

AB² = (t1² + r²) + (t2² + r²) - 2r²

AB² = t1² + t2²

Therefore, AB² = t1² + t2² .