if takes one minute to fill 4/5 of a tank .how much time is needed to fill an empty tank
Answers
Answered by
32
Let the total amount be x
4x/5=60
x=75
So 75 seconds are required to fill tank
1min 15 seconds
pls mark as brainliest
4x/5=60
x=75
So 75 seconds are required to fill tank
1min 15 seconds
pls mark as brainliest
mathsteacher:
how 75 came
4x/5=60
x=60×5/4
x=300/4
x=75
ok
pls mark as brainliest
ty
thanks
welcm
Answered by
6
Time taken to fill 4/5 of tank = 1 minute
Time taken to fill an empty tank = x
From above
4x / 5 = 1
x = 5/4
x = 1.25 minutes
x = 1 minute + 0.25 minutes
x = 1 minute + 0.25×60 seconds
x = 1 minute 15 seconds
Time taken to fill an empty tank is 1 minute 15 seconds
Time taken to fill an empty tank = x
From above
4x / 5 = 1
x = 5/4
x = 1.25 minutes
x = 1 minute + 0.25 minutes
x = 1 minute + 0.25×60 seconds
x = 1 minute 15 seconds
Time taken to fill an empty tank is 1 minute 15 seconds
but answer is 1 min 15 second
80seconds=1min 15 second
@MathsTeacher answer edited.
@Indresh 80 seconds ≠ 1 min 15 seconds
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