Question

If tan 0 = 1 then, find the values at
sin 0+ cose
sec0+ coseco​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

tan 0=1

sin0/cos0=1

sin0=cos0_eq1

So now,sin0+cos0

=sin0+sin0(from eq_1)

=2sin0

And sec0+cisec0

=1/cos0+1/sin0

=sin0+cos0÷sin0.cos0

=sin0+sin0÷sin0.sin0

=2sin0/sin^20

=2/sin0

Now, sin0+cos0÷sec0+cosec0

=2sin0÷2/sin0

=2sin0×sin0/2

=sin0×sin0

=sin^20(ans)

Hope it is helpful.