Question

If tan 0 + cot 0 = 2, then the value of tan-0+ cot?0 is: (a)-2 (b) 3 (6) 1 (d) 2​

Answer 1

Answer:

Correct option is

A

2

tanθ+cotθ=2

Squaring both sides;

(tanθ+cotθ)

2

=2

2

⇒tan

2

θ+cot

2

θ+2tanθcotθ=4

⇒tan

2

θ+cot

2

θ+2=4

⇒tan

2

θ+cot

2

θ=2