If tanθ= 1/2, then evaluate [(Cosθ/Sinθ) + {Sinθ/(1+Cosθ)}]
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Draw the triangle
you will find that as tanθ = perpendicular/base
perpendicular = x
base = 2x
which means hypotenuse = √5
To find=>[(1/tanθ)+{sinθ/(1+cosθ}]
=>[2+{(1/√5)/(1+2/√5)}]
=>2+ [(1/√5)*{(2√5-1)/(10-1)}] ---------------------- Factorizing the denominator
=>2+(2√5-1)/(9√5) -------- Answer(You can simplify more to your need
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