Question

It is given that 3899= 125x 31+ 24. The least positive integer that should be subtracted from
3899 so that the difference becomes divisible by 125 and 31

Answer 1

Answer:

24

Step-by-step explanation:

It is given that 3899= 125x 31+ 24. The least positive integer that should be subtracted from  

3899 so that the difference becomes divisible by 125 and 31

3899 = 125 * 31  + 24

Number  = Divisor * Quotient  + remainder

Remainder is required to subtract from the number so that resultant number is divisible by Divisor /quotient

Here divisor & Quotient are 125 & 31

Number = 3899

Remainder = 24

24 is the least positive integer that should be subtracted from  3899 so that the difference becomes divisible by 125 and 31