If x+y=4, xy=5 find x³+y³ using identity
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x3+y3=(x+y)(x2+y2+2xy)
=(5)(x2+y2+8)
=(5)(x+y)+(x-y)+(8)
=5 (4)+(x-y)+8
=60+(x-y)
siva211970yahoocom:
can you send me the answer for another question
which question
if a+b+ =15,a²+b²+c²=175.find ab+bc+ca
from the identity we have (a+b+c)^2=a^2+b^2+c^2+2 (ab+bc+ca)
root?
not root its square
ok
can you send photo for that
no sorry not right now
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