Math, asked by Bestbou12, 1 year ago

if tan(α)=1/3 and tan(x)=1/7 then 2α+x​

Answers

Answered by Anonymous
19

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нεяε ¡ร тнε คหรωεя

тคห x = 2/3 คหd тคห ყ = 3/4.

หσω, тคห (x+ყ) = [тคห x + тคห ყ]/[1 - тคห x*тคห ყ]

= [(2/3) + (3/4)]/[1 - (2/3)*(3/4)]

= [8+9]/12*[1 - (2/3)*(3/4)]

= 17/12*(1/2)

= 17/6

คหรωεя: тคห (x+ყ) = 17/6.

нσpε ¡т нεłpร

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adikarthikeya: Tan*-1 ( 11/2)
adikarthikeya: according to the formulae "tan*-1(x) +tan*-1(y) = tan*-1(x+y/1-xy)
Answered by Bhasksr
7

HERE IS YOUR ANSWER MATE

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hope it helps you mate :)

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