Question

If tan−1x+tan−1y+tan−1z=π2,x,y,z>0, then find the value of xy+yz+zx

Answer 1

\left[x \right] = \left[ \frac{ - \left( yz+zx\right) }{y}\right][x]=[​y​​−(yz+zx)​​] totally value.