Question

If tan=2/3 than find sin + cos/ sec+cosec​

Answer 1

Answer:

$\tan = \frac{2}{3} \: \: then \: \: \cot = \frac{1}{ \tan} = \frac{3}{2} \: \: and \: \: \sin = 2 \: \: and \: \: \: cos = 3\\ now \: \: \: \frac{ \sin + \cos }{ \sec + \csc} = \frac{ \cos( \tan + 1) }{ \sec( 1+ \tan) } = \frac{ \cos {}^{2}( \tan + 1)}{ 1 + \tan } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \cos {}^{2} = 3 {}^{2} = 9$

Answer 2

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answer is 6

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