Question

if tan(2A+3 B)=root 3 and tan(3A+2B)=1/root 3 then find A and B​

Answer 1

tan(2A+3B)=√3

tan(2A+3B)=tan60°

2A+3B=60°→1

tan(3A+2B)=1/√3

tan(3A+2B)=tan30°

3A+2B=30°→2

Solve Equation 1 and 2

B=24

Substitute B value in equation 1

2A+3(24)=60

2A+72=60

2A=-12

A=-6

So, The value of A is -6 and B is 24.....

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