Question

If tan 2A = cot( A-18),Where 2A is an acute angle,find the value of A

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Answer 1

tan2A=tan(90-A+18)((((((cotA=Tan(90-A)is a formula)))))
2A=90-A+18
3A=108°
A=108/3
A=36°/////
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Answer 2

Given

tan2A = cot(A- 18°)

---> cot (90° - 2A) = cot (A - 18°)   [Since tan A = cot (90° - A) ]

Removing cot, we get

90 - 2A = A - 18

---> 3A = 108°

--> A = 36°