If tan 2A= cot (A- 18°)where 2 A is an acute angle find the value of A
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tanA=cot(90-A)
so tan2A=cot(90-2A)=cot(A-18)
so 90-2A=A-18
108=3A
so A=36
I HOPE IT WILL HELP YOU
so tan2A=cot(90-2A)=cot(A-18)
so 90-2A=A-18
108=3A
so A=36
I HOPE IT WILL HELP YOU
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5
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