If tan 2A = cot (A - 18°),where 2A is an acute angle ,find thr value of A.
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Answered by
14
Hii There!!
Since, tan theeta= cot (90°- theeta)
=) tan 2A = cot (90°-theeta)
=) cot (90°-2A) = cot (A-18°)
cot is cancelled out on both sides [LHS and RHS]
=) 90°- 2A = A-18°
=) -2A-A = -18°-90°
=) -3A =-108° ( negative sign is cancelled)
=) A= 108/3
=) A= 36°
Hope it helps ^_^
Since, tan theeta= cot (90°- theeta)
=) tan 2A = cot (90°-theeta)
=) cot (90°-2A) = cot (A-18°)
cot is cancelled out on both sides [LHS and RHS]
=) 90°- 2A = A-18°
=) -2A-A = -18°-90°
=) -3A =-108° ( negative sign is cancelled)
=) A= 108/3
=) A= 36°
Hope it helps ^_^
Answered by
3
=tan 2A = cot (A-18')
=cot(90'-2A) = cot (A-18') •••tan(90-Q)= cot
=90'-2A = A-18'
=90'+18' = 2A+A
=108' = 3A
A= 108'/3
A=36'
=cot(90'-2A) = cot (A-18') •••tan(90-Q)= cot
=90'-2A = A-18'
=90'+18' = 2A+A
=108' = 3A
A= 108'/3
A=36'
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