if tan 2A is equal to cos bracket a minus 18 degree bracket close where to a is an acute angle find the value of V
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tan 2A =cos (90-(A-18)
=tan 2A=tan(90-A+18)
=2A=108-A
=3A=108
=A=108/3=36
=tan 2A=tan(90-A+18)
=2A=108-A
=3A=108
=A=108/3=36
kiran243:
but it is wrong s......
Answered by
2
the question should be cot theta not cos theta .
tan2A = cot( A-18)
cot (90-2A) = cot (A-18)
90-2A = A-18
3A= 108
A= 36
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