Question

If tan Ꝋ = 3/4, find sin Ꝋ, cos Ꝋ, sec Ꝋ, cot Ꝋ and cosec Ꝋ

Please answer this fast with full explanation. ​

Answer 1

Given,

tan theta = 3/4

tan theta = opposite/adjacent

So, opposite/adjacent = 3/4

So

opposite= 3

adjacent= 4

Using Pythagoras theorem:-

(3)²+(4)²=(5)²

9+16=25

so hypotenuse=5

sin theta= opposite/hypotenuse =3/5

cos theta =adjacent/hypotenuse =4/5

tan theta= opposite/adjacent = 3/4

cosec theta = 1/sin theta = 5/3

sec theta = 1/cos theta = 5/4

cot theta = 1/tan theta = 4/3

Answer 2

Answer:

Given,

tan theta = 3/4

tan theta = opposite/adjacent

So, opposite/adjacent = 3/4

So

opposite= 3

adjacent= 4

Using Pythagoras theorem:-

(3)²+(4)²=(5)²

9+16=25

so hypotenuse=5

sin theta= opposite/hypotenuse =3/5

cos theta =adjacent/hypotenuse =4/5

tan theta= opposite/adjacent = 3/4

cosec theta = 1/sin theta = 5/3

sec theta = 1/cos theta = 5/4

cot theta = 1/tan theta = 4/3

Step-by-step explanation: