if tan 3. tan 6=1 then the value of thita
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let A = thita
tan3Atan6A = 1 ----(1)
tan(3A+6A) = 1
tan9A = 1
tan9A = tan45°
9A = 45°
A = 45 °/9 = 5°
A = 5°
hence value of thita = 5°
or if you want to check that your answer is correct or not .then put value in "A " eq.(1)
tan3(5)tan6(5) = 1
tan15tan30 = 1
tan(15+30 ) = 1
tan45° = 1
1 = 1
L.H.S =R.H.S
hence your value of thita(A) is correct.
hope it helps !
thank you!
tan3Atan6A = 1 ----(1)
tan(3A+6A) = 1
tan9A = 1
tan9A = tan45°
9A = 45°
A = 45 °/9 = 5°
A = 5°
hence value of thita = 5°
or if you want to check that your answer is correct or not .then put value in "A " eq.(1)
tan3(5)tan6(5) = 1
tan15tan30 = 1
tan(15+30 ) = 1
tan45° = 1
1 = 1
L.H.S =R.H.S
hence your value of thita(A) is correct.
hope it helps !
thank you!
TheLostMonk:
i said you could add then by taking out tan(common ) if there is value in the other side =1 ..etc
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