If tan 4=√3, find the sin A
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tan = √3/4 tan =p/b p=√3. b=4
sin = p /h
h^2=b^2+p^2
h^2= (4)^2+(√3)^2
h^2= 16+3
h=√19
put it in sin
sin √3/√19
please mark me brainliest bcz I need it
sin = p /h
h^2=b^2+p^2
h^2= (4)^2+(√3)^2
h^2= 16+3
h=√19
put it in sin
sin √3/√19
please mark me brainliest bcz I need it
ankush8116:
thanks a lots
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