If tanθ =4/3, find the value of 5sinθ+2cosθ/3sinθ -cosθ
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tanA=P/B=4/3
BY PYTHAGOREOUS THEOREM
(H)2=(P)2+(B)2
(H)2=((4)2+(3)2
(H)2=16+9
=25
(H)2=5×5
H=5
SIN A=P/H=4/5
COS A=B/H
5×4/5+2×3/5/3×4/5_3/5
20/5+6/5/12/5_3/5
26/5/9/5
26×5/5×9
26/9
BY PYTHAGOREOUS THEOREM
(H)2=(P)2+(B)2
(H)2=((4)2+(3)2
(H)2=16+9
=25
(H)2=5×5
H=5
SIN A=P/H=4/5
COS A=B/H
5×4/5+2×3/5/3×4/5_3/5
20/5+6/5/12/5_3/5
26/5/9/5
26×5/5×9
26/9
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