Question

if tanθ=4 , then the value of (tan²θ + 2sec²θ) = ????​

Answer 1

If tan θ = 4, tan² θ = 16

tan² θ + 2sec² θ = tan² θ + 2(1 + tan² θ) [Identity: tan² x + 1 = sec² x]

» tan² θ + 2 + 2tan² θ

» 3tan² θ + 2

» 3(16) + 2

» 48 + 2

» 50