If Tan A = 1/2 and Tan B = 1/3
By using Tan(A+B) = (Tan A + Tan B )/(1-Tan A.Tan B ) Prove that A+B=45°
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Step-by-step explanation:
Given that, tanA = 1/3
tanB = 1/2
tan (A+ B) = ( tanA + tanB) / (1 - tanA tanB)
= (1/3 +1/2) / (1- 1/3×1/2)
= (5/6) / ( 1- 1/6)
= (5/6)/(5/6)
tan (A+B) =1
(A + B) = tan(−1)1
( A+ B) = 45∘
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