If tan A=1/2 ,tanB=1/3,then tan(A+B)=----
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hey, here is your answer......
given, tanA = 1/2.... tanB = 1/3....
need to find the value of tan(A+B) .....
tan(A+B) = [tanA+tanB]/ [1 - (tanA.tanB)]......
tan(A+B) = [1/2 + 1/3]/[1 - (1/2 × 1/3)]......
tan(A+B) = [5/6]/[1 - (1/6)].......
tan(A+B) = [5/6]/[(6-1)/6].....
tan(A+B) = [5/6]/[5/6].....
tan(A+B) = 1.....
hope this helps you.....
thank you......
plzz mark me as brainliest......
given, tanA = 1/2.... tanB = 1/3....
need to find the value of tan(A+B) .....
tan(A+B) = [tanA+tanB]/ [1 - (tanA.tanB)]......
tan(A+B) = [1/2 + 1/3]/[1 - (1/2 × 1/3)]......
tan(A+B) = [5/6]/[1 - (1/6)].......
tan(A+B) = [5/6]/[(6-1)/6].....
tan(A+B) = [5/6]/[5/6].....
tan(A+B) = 1.....
hope this helps you.....
thank you......
plzz mark me as brainliest......
pikachu119:
no need pf please
good explanation
hope you become a genius in this app
the problem too easy by seeing your answer
thank you.... for ur compliments.....✌️
can u plzz mark me as brainliest❤
sure
tq..... :-)
all the best for exam
plzzzzzz mark me as brainliest.......................
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